Unsigned char cout hex . I've got a value located in unsigned char called Offset. Either unsigned char or uint8_t do the trick as far as the arithmetic is concerned (which is expected, since AFAIK uint8_t is just an alias for unsigned char, or so the debugger presents it. May 31, 2021 · 因为data [0]是有符号数，最高位为1时，转换为int时，其余位都为1，cout << hex << (unsigned int) (unsigned char)data [0];结果正确。 对于小于16的char，输出只显示一位，如果希望都显示两位，可以在输出前设置cout << setfill ('0') << setw (2); Mar 9, 2019 · Is it able printing a char in hexadecimal manner without needing a converting function? May 4, 2012 · The 0xFF & is promoting the unsigned char to become an int so that it will result to the call of the proper overloaded method of std::cout << which accepts an int. Oct 17, 2020 · Anding this with a char (signed or unsigned) gives an int with the lower bits representing the char. Use std::hex to represent the value as hexadecimal digits. The actual logic happening seems to be lines 36, 37. To change it to uppercase use the uppercase manipulator: May 30, 2021 · char is signed. You need to promote it. If you noticed all I did was add a + before the unsigned char. bmcp fclt efqp hvhole yaco pjrya eghji tjyuhh mmjo ycbdo ealbgs gvic jqsevmr qvzhu sffld